For number 16, I won't give you the answer, but write the left hand side in the numerator (above the fraction) and the right hand side in the denominator (under the fraction). Anything that appears in both the top and bottom can be cancelled. Just another little hint: 2/4 = 1/2. This may be obvious, but you never know.

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09-15-2009 #21Tarsier Level Designer
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Thanks!
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09-15-2009 #22Sackperson Sergeant
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09-15-2009 #23ʇuɐǝƃɹǝS uosɹǝdʞɔɐS
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ooh I get it, thanks for the hint!For number 16, I won't give you the answer, but write the left hand side in the numerator (above the fraction) and the right hand side in the denominator (under the fraction). Anything that appears in both the top and bottom can be cancelled. Just another little hint: 2/4 = 1/2. This may be obvious, but you never know.
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09-15-2009 #24
Sorry got picked up early so I'm home now

Though I'll be busy trying to find out where the hell I enter my batman arkham aylum code...
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09-16-2009 #25

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09-16-2009 #26Thread
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Meh. i was just about to ask a question about my homework too. i really don't want to be a leach, but its too late to ask someone for help in real life, and my trig book doesn't give any explanation as to what i'm supposed to do. (i'm sorry, i just don't want to get a 0)
mine's just a simple proof in trig 101. shouldn't be to hard compared to the calculus question...
"show that each of the following statements is an identity by transforming the left side of each one into the right side"
tan²Θ + 1 = sec²Θ
secΘ cotΘ - sinΘ = (cos²Θ)/(sinΘ)
(sinΘ - cosΘ)² - 1 = -2 sinΘ cosΘ
I already know my reciprocal and quotient trigonometric identities - i just don't see how to apply them with the addition and subtraction included in the questions. i don't blame anyone who calls me a leech for this, but the only other place i could possibly ask this late at night is at the other community forum i go to - and knowing them they would probably answer the question in assembly language or something just to spite me.
sorry ;_;
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